The number of electrons for `Zn^(2+)` cation that have the value of azimuthal quantum number `=0` is:

Explanation

To determine the number of electrons in the `Zn^(2+)` cation that have an azimuthal quantum number (l) equal to 0, we can follow these steps:

### Step 1: Understand Quantum Numbers
The azimuthal quantum number (l) indicates the shape of the orbital. For l = 0, the corresponding orbital is the s orbital.

**Hint:** Remember that the value of l corresponds to different types of orbitals:
- l = 0 for s
- l = 1 for p
- l = 2 for d
- l = 3 for f

### Step 2: Determine the Atomic Number of Zinc
Zinc (Zn) has an atomic number of 30, which means it has 30 electrons in its neutral state.

**Hint:** The atomic number of an element tells you the number of protons and, in a neutral atom, the number of electrons.

### Step 3: Write the Electron Configuration of Neutral Zinc
The electron configuration of neutral zinc (Zn) is:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰

**Hint:** The electron configuration shows how the electrons are distributed among the various orbitals.

### Step 4: Determine the Electron Configuration of `Zn^(2+)`
When zinc loses two electrons to form the `Zn^(2+)` cation, the electrons are removed from the outermost shell first, which includes the 4s orbital. Thus, the electron configuration for `Zn^(2+)` becomes:
1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰

**Hint:** When forming cations, electrons are removed from the highest energy level (n) first.

### Step 5: Identify Electrons with Azimuthal Quantum Number l = 0
Since we are looking for electrons with l = 0 (s orbital), we need to count the electrons in the s orbitals from the electron configuration of `Zn^(2+)`:
- 1s² contributes 2 electrons
- 2s² contributes 2 electrons
- 3s² contributes 2 electrons

Adding these together gives:
2 (from 1s) + 2 (from 2s) + 2 (from 3s) = 6 electrons

**Hint:** Only the s orbitals contribute to the count for l = 0.

### Final Answer
The number of electrons in `Zn^(2+)` that have the azimuthal quantum number equal to 0 is **6**.