A satellite of mass `m` revolves around the earth of radius `R` at a height x from its surface. It g is the acceleration due to gravity on the surface of the earth, the orbit speed of the satellite is

Options

A. gx
B. `((gR^2)/(R+x))^(1//2)`
C. `(gR^2)/(R+x)`
D. `(gR)/(R-x)`

Answer

B

Explanation

`v_0=sqrt((GM)/(R+x))=sqrt((gR^2)/(R+x))`