A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is `11 kms^(-1)`, the escape velocity from the surface of the planet would be

Options

A. 1.1 km/s
B. 11 km/s
C. 110 km/s
D. 0.11 km/s

Answer

C

Explanation

Mass of planet `M_p=10M_e`
Where `M_e` is the mass of the earth.
Radius of planet `R_P=R_e/10` Where `R_e` is the radius of the earth .
Escape velocity from planet surface
`v_p=sqrt((2GM_p)/R_p)=sqrt((2G(10M_e))/((R_e//10)))=10sqrt((2GM_e)/(R_e))=10v_e` = 110 km/s