If the angular momentum of a planet of mass m, moving around the Sun in a circular orbit is L, about the center of the Sun, its areal velocity is :

Options

A. `L/(2m)`
B. `(4L)/m`
C. `L/m`
D. `(2L)/m`

Answer

A

Explanation

`dA=1/2R^2 d theta`
`(dA)/(dt)=1/2 R^2 (d theta)/(d t) =R^2/2 omega`
`L=mR^2 omega therefore (dA)/(dt) =R^2/2 (L/(mR^2)) =L/(2m)`