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A gestationary satellite is orbiting the...

A gestationary satellite is orbiting the earth at a height 6 R above the surface of earth, where R is the radius of the earth. The time period of another statellight at a height of 2.5 R from the surface of earth in hours is

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The correct Answer is:
6.45 h
According to Kepler's law, `T_1^2/T_2^2 =R_1^3/R_2^3`
`rArr (24xx24)/T_2^2 =(6xx6xx6xxR^3)/(2.5xx2.5xx2.5xxR^3) rArr T_2^2 =(24xx24xx2.5xx2.5xx2.5)/(6xx6xx6) rArr T_2=6.45 h`
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