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If the area enclosed between the curves `y=kx^2` and `x=ky^2`, where `kgt0`, is 1 square unit. Then k is: (a) `1/sqrt(3)` (b) `sqrt(3)/2` (c) `2/sqrt(3)` (d) `sqrt(3)`

A

`(sqrt(3))/(2)`

B

`(2)/(sqrt(3))`

C

`sqrt(3)`

D

`(1)/(sqrt(3))`

Text Solution

Verified by Experts

The correct Answer is:
D
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