Find the ratio of de Broglie wavelength of a proton and as `alpha`-particle which have been accelerated through same potential difference.

Explanation

Use Davisson and Germer’s modification `(lamda_(alpha))/(lamda_(p)) = sqrt(((e_(p) m_(p)))/((e_(alpha) m_(alpha)))) = sqrt((1 xx 1)/((2 xx4))) = (1)/(2 sqrt2)` as potential difference is same