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derivative of cos(x^4)...

derivative of `cos(x^4)`

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To find the derivative of the function \( f(x) = \cos(x^4) \), we will use the chain rule. The chain rule states that if you have a composite function \( f(g(x)) \), then the derivative \( f'(g(x)) \cdot g'(x) \). ### Step-by-Step Solution: 1. **Identify the outer and inner functions**: - The outer function is \( f(u) = \cos(u) \) where \( u = x^4 \). - The inner function is \( g(x) = x^4 \). 2. **Differentiate the outer function**: - The derivative of \( f(u) = \cos(u) \) is \( f'(u) = -\sin(u) \). 3. **Differentiate the inner function**: - The derivative of \( g(x) = x^4 \) is \( g'(x) = 4x^3 \). 4. **Apply the chain rule**: - According to the chain rule, the derivative of \( f(g(x)) \) is given by: \[ f'(g(x)) \cdot g'(x) = -\sin(g(x)) \cdot g'(x) \] - Substituting \( g(x) \) back in: \[ f'(x) = -\sin(x^4) \cdot (4x^3) \] 5. **Combine the results**: - Therefore, the derivative of \( \cos(x^4) \) is: \[ f'(x) = -4x^3 \sin(x^4) \] ### Final Answer: The derivative of \( \cos(x^4) \) is: \[ f'(x) = -4x^3 \sin(x^4) \] ---
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Knowledge Check

  • The derivative of cos^(-1)((sinx+cosx)/(sqrt(2))),-(pi)/(4)ltxlt(pi)/(4) , w.r.t.x is

    A
    `(1)/(sqrt(2))`
    B
    1
    C
    `-1`
    D
    none of these
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