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Find dy/dx if y=tan^2((pix^2)/2)...

Find dy/dx if y=`tan^2((pix^2)/2)`

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To find \(\frac{dy}{dx}\) for the function \(y = \tan^2\left(\frac{\pi x^2}{2}\right)\), we will use the chain rule and the power rule of differentiation. Here’s a step-by-step solution: ### Step 1: Identify the function Given: \[ y = \tan^2\left(\frac{\pi x^2}{2}\right) \] ### Step 2: Differentiate using the chain rule We will differentiate \(y\) with respect to \(x\). Using the chain rule, we have: \[ \frac{dy}{dx} = 2 \tan\left(\frac{\pi x^2}{2}\right) \cdot \frac{d}{dx}\left(\tan\left(\frac{\pi x^2}{2}\right)\right) \] ### Step 3: Differentiate \(\tan\left(\frac{\pi x^2}{2}\right)\) The derivative of \(\tan(u)\) is \(\sec^2(u) \cdot \frac{du}{dx}\), where \(u = \frac{\pi x^2}{2}\). First, we find \(\frac{du}{dx}\): \[ u = \frac{\pi x^2}{2} \implies \frac{du}{dx} = \frac{\pi}{2} \cdot 2x = \pi x \] Now, we can differentiate \(\tan\left(\frac{\pi x^2}{2}\right)\): \[ \frac{d}{dx}\left(\tan\left(\frac{\pi x^2}{2}\right)\right) = \sec^2\left(\frac{\pi x^2}{2}\right) \cdot \pi x \] ### Step 4: Substitute back into the derivative Now we substitute back into our expression for \(\frac{dy}{dx}\): \[ \frac{dy}{dx} = 2 \tan\left(\frac{\pi x^2}{2}\right) \cdot \sec^2\left(\frac{\pi x^2}{2}\right) \cdot \pi x \] ### Step 5: Simplify the expression Thus, we can write the final expression for \(\frac{dy}{dx}\) as: \[ \frac{dy}{dx} = 2\pi x \tan\left(\frac{\pi x^2}{2}\right) \sec^2\left(\frac{\pi x^2}{2}\right) \] ### Final Result \[ \frac{dy}{dx} = 2\pi x \tan\left(\frac{\pi x^2}{2}\right) \sec^2\left(\frac{\pi x^2}{2}\right) \] ---
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