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y = sin ^(-1)((1 - x^(2))/(1+ x^(2))) 0...

`y = sin ^(-1)((1 - x^(2))/(1+ x^(2))) 0 lt x lt 1` find dy/dx

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To find the derivative \( \frac{dy}{dx} \) for the function \( y = \sin^{-1}\left(\frac{1 - x^2}{1 + x^2}\right) \) where \( 0 < x < 1 \), we can follow these steps: ### Step 1: Substitute \( x \) with \( \tan \theta \) Let \( x = \tan \theta \). Then, we have: \[ \theta = \tan^{-1}(x) \] ...
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