If `x=sin^3t/(sqrtcos2t), y=cos^3t/sqrt(cos2t)` show that `dy/dx =0 ` at ` t=pi/6`

Explanation

To show that \(\frac{dy}{dx} = 0\) at \(t = \frac{\pi}{6}\) for the given functions \(x = \frac{\sin^3 t}{\sqrt{\cos 2t}}\) and \(y = \frac{\cos^3 t}{\sqrt{\cos 2t}}\), we will follow these steps:

### Step 1: Differentiate \(x\) with respect to \(t\)

We have:
\[ x = \frac{\sin^3 t}{\sqrt{\cos 2t}} \]
...