The number of N-6=6(log)(10)2+(log)(10)3...

The number of `N-6=6(log)_(10)2+(log)_(10)31` lies between two successive integers whose sum is equal to 5 (b) 7 (c) 9 (c) 10

A

5

B

7

C

9

D

10

Text Solution

Verified by Experts

The correct Answer is:

B

`N = log_(10) 64+log_(10) 31 = log_(10) 1984`.Therefore,
` 3 lt N lt 4 rArr 7`

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