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Given that log(2)=0. 3010 , the number ...

Given that `log(2)=0. 3010 ,` the number of digits in the number `2000^(2000)` is 6601 (b) 6602 (c) 6603 (d) 6604

A

6601

B

6602

C

6603

D

6604

Text Solution

Verified by Experts

The correct Answer is:
C
Let ` x = 2000^(2000)`
`log x = 2000 log_(10) (2000)`
` = 2000 (log_(10)2+3)`
` = 2000(3.3010) = 6602`
Therefore, the number of digits is 6603.
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