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If `a , b , c` are consecutive positive integers and log `(log(1+a c)=2K ,` then the value of `K` is `logb` (b) `loga` (c) 2 (d) 1

A

log b

B

log a

C

2

D

1

Text Solution

Verified by Experts

The correct Answer is:
A
Let ` a = x - 1, b = x, c = x+1`
Now `log(1+ac)=log [1+(x-1)(x+1)]`
` = log x^(2) = 2 log x = 2 log b`
` rArr K = log b`
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