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The value of int(0)^(4pi)log(e)|3sinx+3s...

The value of `int_(0)^(4pi)log_(e)|3sinx+3sqrt(3) cos x|dx` then the value of I is equal to

A

`pi log_(e)3`

B

`2 pi log_(e)3`

C

`4pilog_(e)3`

D

`8pilog_(e)3`

Text Solution

Verified by Experts

The correct Answer is:
C

`I=int_(0)^(4pi)log_(e)|6sin(x+(pi)/3)|dx`
`=int_(0)^(4pi)log_(e) 6 dx+int_(0)^(4pi)|sin(x+(pi)/3)|dx`
`=4pi log_(e) 6+4int_(0)^(pi)log_(e)|sinx|dx`
`=4pi log_(e)6+8int_(0)^(pi//2) log_(e)|sinx|dx`
`=4pi log_(e)6-4log_(e)2`
`=4pi log_(e)3`
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