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The value of int0^1e^(x^2-x)dx is (a) <...

The value of `int_0^1e^(x^2-x)`dx` is (a) `<1` (b) `>1` (c) `> `e^(-1/4)` (d)` < e^(-1/4)`

A

`lt1`

B

`gt1`

C

`gte^(-1/4)`

D

`lte^(-1/4)`

Text Solution

Verified by Experts

The correct Answer is:
A, C
`int_(0)^(1)e^(x^(2)-x)dx`
For `x epsilon(0,1),x^(2)-x epsilon(-1//4,0)`
`:.e^(-1//4)lt e^(x^(2)-x)lte^(0)`
or `e^(-1/4)lt int_(0)^(1)e^(x^(2)-x)dxlt1`
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