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If y log x= x-y, prove that (dy)/(dx)= (...

If `y log x= x-y`, prove that `(dy)/(dx)= (log x)/((1+log x)^(2))`

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`"We have "x^(y)=e^(x-y)`
`"or "e^(ylog x)=e^(x-y)" "[becausex^(y)=e^(log x^(y))=e^(y log x)]`
`"or "ylog x = x-y`
`"or y=(x)/(1+log x)`
On differentiating both the sides w.r.t. x, we get
`(dy)/(dx)=((1+log x)xx1-x(0+(1)/(x)))/((1+ log x)^(2))=(log x)/((1+ log x )^(2))`
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