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If sinx+sin^2x=1n then the value of cos^...

If `sinx+sin^2x=1`n then the value of `cos^12x+3cos^10x+3cos^8x+cos^6x-1` is equal to

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The correct Answer is:
3
We have `sinx+sin^2x=1`
`or sinx=1-sin^2xorsinx=cos^2x`
Now, `cos^12x+3sin^10x+3sin^4x+sin^3x-2`
`=sin^6x+3sin^5x+3sin^4x-2`
`=(sin^2x)^3+3(sin^2x)^2sinx+3(sin^2x)`
`(sinx)^2+(sinx)^3-2`
`=(sin^2x+sinx)^3-2=(1)^3-2=-1`
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CENGAGE PUBLICATION-TRIGONOMETRIC FUNCTIONS -Exercises
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  2. Which of the following is not the quadratic equation whose roots are c...

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  3. If sinx+sin^2x=1n then the value of cos^12x+3cos^10x+3cos^8x+cos^6x-1 ...

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