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A right triangle has perimeter of length...

A right triangle has perimeter of length 7 and hypotenuse of length `3.` If `theta` is the larger non-right angle in the triangle, then the value of `costheta equal`

A

`(sqrt6-sqrt2)/4`

B

`(4+sqrt2)/6`

C

`(4-sqrt2)/6`

D

`(4-sqrt2)/6`

Text Solution

Verified by Experts

The correct Answer is:
D

`"Perimeter "=7=3sintheta+3costheta+3," where " 45^@ltthetalt90^@`
`sintheta+costheta=4/3 ...(i)`
Since `(sintheta+costheta)^2+(sintheta-costheta)^2=2`, we have
`(sintheta-costheta)^2=2-(4/3)^2`

`rArrsintheta-costheta=sqrt2/3 ...(ii)`
From (i) and (ii),`costheta=(4-sqrt2)/6`
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