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Four numbers n1,n2,n3a n dn4 are given a...

Four numbers `n_1,n_2,n_3a n dn_4` are given as `n_1=sin15^0-cos15^0,n_2=cos93^0+sin93^0,n_3=tan27^0-cot27^0, n_4=cot127^0+tan127^0dot` `n_1<0` (b) `n_2<0` (c) `n_3<0` (d) `n_4<0`

A

`n_1lt0`

B

`n_2lt0`

C

`n_3lt0`

D

`n_4lt0`

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
`n_1=sin15^@-cos15^@lt-ve" "(cos15^@gtsin15^@)`
`n_2=cos93^@+sin93^@`
`=-sin3^@+cos3@gt0" "(cos3^@gtsin3^@)`
`n_3=tan27^@-cot27^@lt0" "(tan27^@ltcot27@)`
`n_4=cot127^@+tan127^@lt0" "(tan127^@,cot127^@lt0)`.
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