Find roots of the equation `(z + 1)^(5) = (z - 1)^(5)`.

Explanation

For `zne1,` given equation can be written as `((z+1)/(z-1))^(5)=1.`
`:." "(z+1)/(z-1)=e^((2kpii)/(5)),"where "k=1,2,3,4`
`implies" "z=(e^(2kpii//5)+1)/(e^(2kpii//5)-1)=(e^(kpii//5)+e^(-kpii//5))/(e^(kpii//5)-e^(-kpii//5))`
`=(2cos(kpi//5))/(2isin(kpi//5))`
`=-icot((kpi)/(5)),k=1,2,3,4`