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IF n=""^m C2 then "^n C2 is equal to...

IF `n=""^m C_2` then `"^n C_2` is equal to

A

`"^(m+1)C_4`

B

`"^(m+2)C_4`

C

`"^(m-1)C_4`

D

`3. "^(m+1)C_4`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem where \( n = \binom{m}{2} \), we need to find \( \binom{n}{2} \). ### Step-by-Step Solution: 1. **Understanding \( n \)**: Given \( n = \binom{m}{2} \), we can express this as: \[ n = \frac{m(m-1)}{2} \] 2. **Finding \( \binom{n}{2} \)**: We need to calculate \( \binom{n}{2} \): \[ \binom{n}{2} = \frac{n(n-1)}{2} \] 3. **Substituting for \( n \)**: Substitute \( n = \frac{m(m-1)}{2} \) into the equation: \[ \binom{n}{2} = \frac{\left(\frac{m(m-1)}{2}\right)\left(\frac{m(m-1)}{2} - 1\right)}{2} \] 4. **Simplifying \( n - 1 \)**: Calculate \( n - 1 \): \[ n - 1 = \frac{m(m-1)}{2} - 1 = \frac{m(m-1) - 2}{2} \] 5. **Substituting \( n - 1 \)**: Substitute \( n - 1 \) back into the equation: \[ \binom{n}{2} = \frac{\left(\frac{m(m-1)}{2}\right)\left(\frac{m(m-1) - 2}{2}\right)}{2} \] 6. **Combining the terms**: Now, we can simplify the expression: \[ \binom{n}{2} = \frac{m(m-1)(m(m-1) - 2)}{8} \] 7. **Final Expression**: The final expression for \( \binom{n}{2} \) can be represented as: \[ \binom{n}{2} = \frac{m(m-1)(m^2 - m - 2)}{8} \] ### Conclusion: Thus, the value of \( \binom{n}{2} \) is: \[ \frac{m(m-1)(m^2 - m - 2)}{8} \]
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ML KHANNA-PERMUTATIONS AND COMBINATIONS -SELF ASSESSMENT TEST
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  18. There are 10 points in a plane, out of these 6 are collinear. The numb...

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  19. IF x,y,r are positive integers then ""^x Cr+""^x C(r-1) . ""^ y C1+ ...

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