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sum (k=m)^n "^k Cr is equal to...

`sum _(k=m)^n "^k C_r` is equal to

A

`"^(n+1) C_(r+1)`

B

`""^(n+1) C_(r+1)- "^n C_r`

C

`""^(n+1) C_(r+1)- "^m C_(r+1)`

D

`""^(n+1) C_(r+1)+ "^n C_(r-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
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