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Calculate without using trignometric tables :`4 cos20^∘−√3cot20^∘`

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Without using trigonometric tables , evaluate : ((tan20^(@))/(cosec70^(@)))^(2)+((cot20^(@))/(sec70^(@)))^2+2tan 15^(@)tan37^(@)tan53^(@)tan60^(@)tan75^(@)

Without using trigonometric tables , prove that : (i) tan20^(@)tan40^(@) tan45^(@)tan50^(@)tan70^(@)=1 (ii) tan1^(@) tan2^(@)tan60^(@)tan88^(@)tan89^(@)=sqrt(3) (iii) cot5^(@)cot10^(@)cot30^(@)cot80^(@)cot85^(@)=sqrt(3) (iv) 4sin10^(@)sin20^(@)sin30^(@)sec70^(@)sec80^(@)=2

Without using trigonometric tables , evaluate : (i) (sin40^(@))/(cos50^(@))+(3tan50^(@))/(cot40^(@)) (ii) (sec37^(@))/("cosec "53^(@))-(tan20^(@))/(cot70^(@)) (iii) (cos74^(@))/(sin16^(@))+(sin12^(@))/(cos78^(@))-sin18^(@)sec72^(@) (iv) sin35^(@)sec55^(@)+(4sec32^(@))/("cosec "58^(@))

Without using trigonometric table, evaluate the following: (cosec^2(90-theta)-tan^2theta)/(4(cos^2 48^@+cos^2 42^@))-(2tan^2 30^@ sec^2 52^@ sin^2 38^@)/(cosec^2 70^@-tan^2 20^@