If `delta_min` is the minimum deviation through a prism and `mu` is refractive index and A is angle of prism

A ray of light suffers minimum deviation through a prism of refractive index sqrt(2) . What is the angle of prism if the angle of incidence is double the angle of refraction within the prism?

Angle of minimum deviation for a prism of refractive index 1.5 is equal to the angle of prism The angle of prism is (cos 41^(@) = 0.75)

The angle of minimum deviation is an equilateral prism of refractive index 1.414 is

The angle of incidence for a ray of light at a refracting surface of a prism is 45^(@) . The angle of prism is 60^(@) . If the ray suffers minimum deviation through the prism. The angle of minimum deviation and refractive index of the material of the prism respectively, are

The angle of incidence for a ray of light at a refracting surface of a prism is 45^(@) . The angle of prism is 60^(@) . If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are :

The angel of incidence for a fay of light at a refracting sufrace of a prism is 45^(@). The angle of prism is 60^(@) If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism repectively, are