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Find energy required to break an alumini...

Find energy required to break an aluminium nucleus into its constituent nucleons (`m_n = 1.00867 u`, ` m_p = 1.00783 u`, `m_Al = 26.98154 u`)

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The energy required to separate the typical middle mass nucleus ._(50)^(120)Sn into its constituent nucleons ( Mass of ._(50)^(120)sn=119.902199u , mass of proton =1.007825 u and mass of neutron =1.008665 u )

What would be the energy required to dissociate completely 1 g of Ca-40 into its constituent, particles? Given: Mass of proton =1.00866 am u , Mass of neutron =1.00866 am u , Mass of Ca-40 =39.97454 am u , (Take 1 am u =931 MeV ).

Calculate the binding energy for nucleon of . _6^(12) C nucleus, if mass of proton m_p = 10078 u , mass of neutron m_n = 1.0087 u , mass of C_12, m_C =12.0000 u , and 1 u =931 .4 MeV .

Find mass defect, binding energy and BE/nucleon for He nuclei. Take mass of He nucleus =4.001509u , M_p = 1.007825u and M_n = 1.008665 u

The neutron separation energy is defined to be the energy required to remove a neutron form nucleus. Obtain the neutron separartion energy of the nuclei ._(20)Ca^(41) and ._(13)Al^(27) form the following data : m(._20Ca^(40))=39.962591u and m(._(20)Ca^(41))=40.962278u m(._(13)Al^(26))=25.986895u and m(._(13)Al^(27))=26.981541u

The minimum frequency of a gamma -ray that causes a deutron to disintegrate into a poton and a neutron is (m_(d)=2.0141 am u, m_p=1.0078 am u, m_n=1.0087 am u.) .

From the given data, the amount of energy required to break the nucleus of aluminium ""_(13)^(27) Al is "_______ "x xx 10^(-3)J. Mass of neutron = 1.00866 u Mass of proton = 1.00726 u Mass of Aluminium nucleus = 27.18846 u (Assume 1 u corresponds to x J of energy) (Round off to the nearest integer)

What is the binding energy per nucleon of _(6)C^(12) nucleus? Given , mass of C^(12) (m_(c))_(m) = 12.000 u Mass of proton m_(p) = 1.0078 u Mass of neutron m_(n) = 1.0087 u and 1 amu = 931.4 MeV

JEE MAINS PREVIOUS YEAR-JEE MAIN 2021-PHYSICS SECTION B
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