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In a !ABC , if 1/(b+c)+1/(c+a)=3/(a+b+c)...

In a `!ABC` , if `1/(b+c)+1/(c+a)=3/(a+b+c)`, then `angleC`=

A

`90^@`

B

`60^@`

C

`45^@`

D

`30^@`

Text Solution

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The correct Answer is:
B
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