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If the triangle be equilateral, then R:r...

If the triangle be equilateral, then `R:r:r_1 =`

A

`1:1:1`

B

`2:1:3`

C

`1:2:3`

D

`3:2:4`

Text Solution

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The correct Answer is:
To solve the problem of finding the ratio \( R : r : r_1 \) for an equilateral triangle, we will follow these steps: ### Step-by-Step Solution: 1. **Understanding the Variables**: - \( R \): Circumradius of the triangle. - \( r \): Inradius of the triangle. - \( r_1 \): Exradius of the triangle. 2. **Finding the Circumradius \( R \)**: - For an equilateral triangle with side length \( a \): \[ R = \frac{abc}{4\Delta} \] Since \( a = b = c = a \) for an equilateral triangle, we can write: \[ R = \frac{a^3}{4\Delta} \] - The area \( \Delta \) of an equilateral triangle is given by: \[ \Delta = \frac{\sqrt{3}}{4} a^2 \] - Substituting \( \Delta \) into the formula for \( R \): \[ R = \frac{a^3}{4 \cdot \frac{\sqrt{3}}{4} a^2} = \frac{a^3}{\sqrt{3} a^2} = \frac{a}{\sqrt{3}} \] 3. **Finding the Inradius \( r \)**: - The inradius \( r \) is given by: \[ r = \frac{\Delta}{s} \] - The semi-perimeter \( s \) of the triangle is: \[ s = \frac{a + a + a}{2} = \frac{3a}{2} \] - Substituting \( \Delta \) and \( s \): \[ r = \frac{\frac{\sqrt{3}}{4} a^2}{\frac{3a}{2}} = \frac{\sqrt{3} a^2}{4} \cdot \frac{2}{3a} = \frac{\sqrt{3} a}{6} \] 4. **Finding the Exradius \( r_1 \)**: - The exradius \( r_1 \) opposite to side \( a \) is given by: \[ r_1 = \frac{\Delta}{s - a} \] - Here, \( s - a = \frac{3a}{2} - a = \frac{a}{2} \): \[ r_1 = \frac{\frac{\sqrt{3}}{4} a^2}{\frac{a}{2}} = \frac{\sqrt{3} a^2}{4} \cdot \frac{2}{a} = \frac{\sqrt{3} a}{2} \] 5. **Finding the Ratio \( R : r : r_1 \)**: - We have: \[ R = \frac{a}{\sqrt{3}}, \quad r = \frac{\sqrt{3} a}{6}, \quad r_1 = \frac{\sqrt{3} a}{2} \] - To find the ratio \( R : r : r_1 \): \[ R : r : r_1 = \frac{a}{\sqrt{3}} : \frac{\sqrt{3} a}{6} : \frac{\sqrt{3} a}{2} \] - Dividing each term by \( a \): \[ = \frac{1}{\sqrt{3}} : \frac{\sqrt{3}}{6} : \frac{\sqrt{3}}{2} \] - To eliminate the fractions, multiply through by \( 6\sqrt{3} \): \[ = 6 : 3 : 9 \] - Simplifying gives: \[ = 2 : 1 : 3 \] ### Final Answer: Thus, the ratio \( R : r : r_1 = 2 : 1 : 3 \).
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