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An Unpolarised light of Intensity I0 is ...

An Unpolarised light of Intensity `I_0` is incident on two polaroids placed co-axially such that `(I_0)/2` intensity is received on screen. By what angle the polaroid placed close to screen should be rotated so that intensity on screen becomes `3/8I_0`

A

`30^@`

B

`60^@`

C

`45^@`

D

`90^@`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the behavior of light as it passes through two polaroids. ### Step-by-step Solution: 1. **Understanding the Initial Conditions**: - We have unpolarized light of intensity \( I_0 \) incident on the first polaroid. - The intensity of light after passing through the first polaroid is given by the formula for unpolarized light passing through a polaroid, which is \( \frac{I_0}{2} \). 2. **Intensity After the First Polaroid**: - The intensity after the first polaroid is: \[ I_1 = \frac{I_0}{2} \] 3. **Setting Up the Second Polaroid**: - The second polaroid is initially aligned with the first one (coaxial). Therefore, the intensity after the second polaroid, without any rotation, would also be \( I_1 = \frac{I_0}{2} \). 4. **Rotating the Second Polaroid**: - We need to rotate the second polaroid by an angle \( \theta \). The intensity of light transmitted through the second polaroid is given by Malus's Law: \[ I_2 = I_1 \cos^2(\theta) \] - Substituting \( I_1 \): \[ I_2 = \frac{I_0}{2} \cos^2(\theta) \] 5. **Setting the Final Intensity**: - According to the problem, we want the intensity on the screen to be \( \frac{3I_0}{8} \): \[ \frac{I_0}{2} \cos^2(\theta) = \frac{3I_0}{8} \] 6. **Solving for \( \cos^2(\theta) \)**: - Dividing both sides by \( I_0 \) and simplifying: \[ \frac{1}{2} \cos^2(\theta) = \frac{3}{8} \] - Multiplying both sides by 2: \[ \cos^2(\theta) = \frac{3}{4} \] 7. **Finding \( \theta \)**: - Taking the square root of both sides: \[ \cos(\theta) = \sqrt{\frac{3}{4}} = \frac{\sqrt{3}}{2} \] - The angle \( \theta \) that satisfies this equation is: \[ \theta = 30^\circ \] ### Final Answer: The angle by which the polaroid placed close to the screen should be rotated is \( 30^\circ \). ---
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