The ratio of acceleration due to gravity at depth 'R' from the surface of planet and at height ' r' from the surface of planet where r

The acceleration due to gravity at a depth R//2 below the surface of the earth is

The ratio of acceleration due to gravity at a height 3R above earth 's surface to the acceleration due to gravity on the surface of the earth is (where R=radius of earth)

Obtain an expression for the acceleration due to gravity on the surface of the earth in terms of mass of the earth and its radius. Discuss the variation of acceleration due to gravity with altitude and depth. If a body is taken to a height R / 4 from the surface of the earth, find percentage decrease in the weight of the body ? Here R is the radius of the earth.

If R is the radius of the earth, then the value of acceleration due to gravity at a height h from the surface of the earth will become half its value on the surface of the earth if

The ratio of acceleration due to gravity at a height 3 R above earth's surface to the acceleration due to gravity on the surface of earth is (R = radius of earth)

The earth is a homogeneous sphere of mass M and radius R. There is another spherical planet of mass M and radius R whose density changes with distance r from the centre as p=p_(0)r. (a) Find the ratio of acceleration due to gravity on the surface of the earth and that on the surface of the planet. (b) Find p_(0).

The acceleration due to gravity near the surface of a planet of radius R and density d is proportional to