The number of oxygen atoms in 4.4 g of `CO_(2)` is approximately

Options

A. `1.2 xx 10^(23)`
B. `6 xx10^(23)`
C. `6 xx 10^(23)`
D. `12xx 10^(23)`

Answer

A

Explanation

44g of `CO_(2)` has `2 xx 6 xx 10^(23)` atoms of oxygen
`4.4g ` of `CO_(2)` has `= (12 xx 10^(23))/(44) xx 4.4 = 1.2 xx 10^(23)` atoms.