What will be the molarity of a solution, which contains 5.85g of `NaCl(s)` per 500mL?

Options

A. 4 mol `L^(-1)`
B. 20 mol `L^(-1)`
C. 0.2 mol `L^(-1)`
D. 2 mol `L^(-1)`

Answer

C

Explanation

Since, molarity (M) is calculated by following equation
Molarity ` = ("weight" xx 100)/("molecular weight" xx "volume(mL)")`
` = (5.85 xx 1000)/(58.5 xx 500) = 0.2 "mol" L^(-1)`