Which of the following statement is incorrect?

Options

A. Pure sodium metal dissolves in liquid ammonia to give blue soluion
B. NaOH reacts with glass to give sodium silicate
C. Aluminium reacts with excess `NaOH` to give `Al(OH)_(3)`
D. `NaHCO_(3)` in heating gives `Na_(2)CO_(3)`

Explanation

To determine which statement is incorrect, we need to analyze the provided statements one by one:

1. **Statement 1**: "Pure sodium metal dissolves in liquid ammonia to give a blue solution."
- This statement is **true**. When sodium metal is dissolved in liquid ammonia, it forms a blue solution due to the presence of ammoniated electrons.

2. **Statement 2**: "When sodium reacts with glass, it gives sodium silicate."
- This statement is also **true**. Sodium reacts with silica (SiO2) present in glass to form sodium silicate (Na2SiO3) and water (H2O).

3. **Statement 3**: "Aluminum reacts with excess NaOH."
- This statement is **true**. Aluminum reacts with sodium hydroxide (NaOH) in a reaction that produces sodium aluminate (NaAl(OH)4) in the presence of excess NaOH.

4. **Statement 4**: "Na reacts with glass to give Na + AlOH."
- This statement is **incorrect**. Sodium does not react with glass to produce Na + AlOH. Instead, it reacts with silica in glass to form sodium silicate.

### Conclusion:
The incorrect statement is the last one: "Na reacts with glass to give Na + AlOH."

### Step-by-Step Solution:
1. Identify the statements provided.
2. Analyze each statement for its accuracy based on chemical reactions.
3. Confirm the true statements regarding sodium's behavior with liquid ammonia, glass, and aluminum.
4. Identify the statement that does not accurately represent the chemical reaction.