`int(1-x)sqrtx dx`

Explanation

`int(1-x)sqrtx dx = int (x^(1//2)-x^(3//2))dx`
`=intx^(1//2)dx-intx^(3//2)dx`
`=(x^(3//2))/(3//2)-(x^(5//2))/(5//2)+c`
`=(2)/(3)x^(3//2)-(2)/(5)x^(5//2)+c`