`sin^(2)(2x+5)`

Explanation

`intsin^(2)(2x+5)dx=int(1-cos(2x+5))/(2)dx`
`=(1)/(2) int 1 dx -(1)/(2) int cos (4x+10)dx`
`=(1)/(2)x-(1)/(2).(1)/(4)sin(4x+10)+c`
`=(1)/(2)x-(1)/(8)sin(4x+10)+c`