`sin^(3)(2x+1)`

Explanation

`intsin^(3)(2x+1)dx`
`=int sin^(2)(2x+1)sin(2x+1)dx`
`=int(1-cos^(2)(2x+1)}sin(2x+1)dx`
`=int(1-t^(2))(dt)/(-2)=-(1)/(2)[t-(t^(3))/(3)]+c`
माना `cos(2x+1)=t`
`rArr -2 sin (2x+1)dx=dt`
`rArr sin(2x+1)dx=(dt)/(2)`
`=-(1)/(2)cos(2x+1)+(1)/(6)cos^(3)(2x+1)+c`