`sin^(3)x cos^(3)x`

Explanation

`int sin^(3)x cos^(3)x dx`
`=intsin^(3)x. cos^(2)x. cosx dx`
`=intsin^(3)x(1-sin^(2)x)cosxdx`
`=intt^(3)(1-t^(2))dt=int(t^(3)-t^(5))dt" माना "sinx=t`
`=(1)/(4)t^(4)-(1)/(6)t^(6)+c" "rArr cos x dx = dt`
`=(1)/(4)sin^(4)x-(1)/(6)sin^(6)x+c`