`int(x^(2))/(1-x^(6))dx`

Explanation

`int(x^(2))/(1-x^(6))dx" माना "x^(3)=t`
`=int(x^(2))/(1-(x^(3))^(2))dx" "rArr 3x^(2)dx=dt`
`=int(1)/(1-t^(2)).(dt)/(3)=(1)/(3) int(1)/(1^(2)-t^(2))dt" "rArr x^(2)dx=(dt)/(3)`
`=(1)/(3).(1)/(2)log|(1+t)/(1-t)|+c=(1)/(6)log|(1+x^(3))/(1-x^(3))|+c`