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sec^2 A(1+sec2A) = 2sec2A...

`sec^2 A(1+sec2A) = 2sec2A`

A

secA

B

2 secA

C

sec2A

D

2 sec 2A

Text Solution

Verified by Experts

The correct Answer is:
D
`(sec2A+1)sec^(2)A=((1+tan^(2)A)/(1-tan^(2)A)+1)(1-tan^(2)A)`
`=(2(1+tan^(2)A))/(1-tan^(2)A)`
`=2sec2A`
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