`(dy)/(dx)` ज्ञात कीजिए|
`x=a sec theta, y= b tan theta`

Explanation

`x = a sec theta`
`rArr" "(dx)/(d theta)=a sec theta tan theta`
तथा `y=b tan theta`
`(dy)/(d theta)=b sec^(2) theta`
अब `(dy)/(dx)=(dy// d theta)/(dx// d theta)=(b sec^(2)theta)/(a sec theta tan theta)`
`=(b)/(a sin theta)=(b)/(a)"cosec "theta`