A `10 g` mixture of glucose and urea present in `250 mL` solution shows the osomotic pressure of `7.4 atm` at `27^(@)C`. Calculate `%` composition of mixture.

Explanation

Let the mixture contains a g glucose and b g urea.
`:.a+b=10` …(i)
Also, `7.4 xx 250/1000=[a/180 + b/60]xx0.0821xx300`
`3a + b =13.52` …(ii)
Solving Eqs. (i) and (ii), we get
`a=1.76 g`
`b=8.24 g`
`%` of glucose =`(1.76/10) xx 100 =17.6`
`%` of urea =`(8.24/10) xx 100 =82.4`