`0.5 g` `KCl` was dissolved in `100 g` water, and the solution, originally at `20^(@)C` froze at `-0.24^(@)C`. Calculate the percentage ionization of salt. `K_(f)` per `1000 g` of water =`1.86^(@)C`.

Explanation

To solve the problem, we need to calculate the percentage ionization of KCl when it is dissolved in water. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the given data
- Mass of KCl (W₂) = 0.5 g
- Mass of water (W₁) = 100 g
- Freezing point of the solution (T_f) = -0.24 °C
- Freezing point of pure water (T_f°) = 0 °C
- K_f (cryoscopic constant) = 1.86 °C/kg
...