Calculate the Van't Hoff factor when `0.1 mol NH_(4)Cl` is dissolved in `1 L` of water. The degree of dissociation of `NH_(4)Cl` is `0.8` and its degree of hydrolysis is `0.1`.

Explanation

Given,
Degree of dissociation`(alpha)=0.8`
Degree of hydrolysis`(h)=0.1`
Considering, ionization of `NH_(4)Cl` (##KSV_PHY_CHM_P2_C02_S01_245_S01.png" width="80%">
`Considering hydrolysis of `NH_(4)^(o+)` ion.

`i"Total moles at equilibrium"/"Initial moles"`
`:. i=(0.2C + 0.8C + 0.8C + 0.8C(1-h)underset(+0.8 Ch )+0.8 Ch)/C`
`=2.68`