The degree of dissociation for `K_(4)[Fe(CN)_(6)]` is `60%`. Calculate the Van't Hoff factor.

Explanation

To calculate the Van't Hoff factor (i) for \( K_4[Fe(CN)_6] \) given a degree of dissociation of 60%, we can follow these steps:

### Step 1: Understand the dissociation of the compound
The dissociation of \( K_4[Fe(CN)_6] \) can be represented as:
\[ K_4[Fe(CN)_6] \rightarrow 4K^+ + [Fe(CN)_6]^{4-} \]
This means that one formula unit of \( K_4[Fe(CN)_6] \) dissociates into 4 potassium ions and 1 hexacyanoferrate ion.
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