The degree of association is `70%` for the following reaction . Calculate the Van't Hoff factor.

Explanation

Total moles=`1-alpha+alpha/2` ltbrge `1-0.7+(0.7/2)`
=`0.3 + 0.35 =0.65` `i="Total moles at equilibrium"/"Initial moles" =(1+4alpha)/(1)=1+4 xx 0.6 =3.4`
Alternative method
`i="Number of ions" xx alpha+(1-alpha)`
`=(1/2xx0.7) + (1-0.7)`
`=0.35 + 0.3 = 0.65`