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A particle at the end of a spring execut...

A particle at the end of a spring executes S.H,M with a period `t_(1)`while the corresponding period for another spring is `t_(2)` . If the period of oscillation with two spring in series is T then

A

`T = t_(1) + t_(2)`

B

`T^(2) = t_(1)^(2) + t_(2)^(2)`

C

`(1)/(T) = (1)/(t_(1)) + (1)/(t_(2))`

D

`(1)/(T^(2)) = (1)/(t_(1)^(2)) + (1)/(t_(2)^(2))`

Text Solution

Verified by Experts

The correct Answer is:
B

`T_(1) = 2pi sqrt((m)/(k_(1))) , T_(2) = 2pi sqrt((m)/(k_(2))) , T = 2pi sqrt((m)/(k_(eq)))`
`K_(eq) = (K_(1)K_(2))/(K_(1)+K_(2))` (for series), `t_(1)^(2) = (2pi m)/(K_(1))`
`t_(2)^(2) =(2pi m)/(K_(2))` and `T^(2) = 2pi m ((1)/(k_(1)) + (1)/(k_(2)))`
`rArr T^(2) = t_(1)^(2) + t_(2)^(2)`
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