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Two particles (A) and (B) of equal masse...

Two particles (A) and (B) of equal masses are suspended from two massless spring of spring of spring constant `k_(1)` and `k_(2)`, respectively, the ratio of amplitude of (A) and (B) is.

A

`(K_(1))/(K_(2))`

B

`(K_(2))/(K_(1))`

C

`sqrt((K_(1))/(K_(2)))`

D

`sqrt((K_(2))/(K_(1)))`

Text Solution

Verified by Experts

The correct Answer is:
D

Maximum velocity `(omega A)` are equal: `omega_(1) A_(1) = omega_(2) A_(2)`
`rArr (A_(1))/(A_(2)) = (omega_(2))/(omega_(1)) = sqrt((K_(2))/(K_(1))) (:' omega = sqrt(K//m))`.
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