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A force of 6.4N stretched a vertical spr...

A force of `6.4N` stretched a vertical spring by `0.1m` .The mass that must be suspended from the spring so that it oscillates with a time period of `pi//4` second

A

`(pi)/(4)kg`

B

`(4)/(pi)kg`

C

`1 kg`

D

`10kg`

Text Solution

Verified by Experts

The correct Answer is:
C
spring constant `K = (6.4)/(0.1) = 64 N//m`.
Now `T = 2pi sqrt((m)/(k))`
or `(pi)/(4) = 2pi sqrt((m)/(64)) :. m = 1kg`
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