A spring of spring constant `K` is cut equal parts of which t part are places in particle and connected will mass `m` shown in figure The time period of oscilation motion of mass `m` is

Options

A. `T = 2 pi sqrt((m)/(nrk))`
B. `T = 2 pi sqrt((nrm)/(K))`
C. `T = 2 pi sqrt((rm)/(nK))`
D. `T = 2 pi sqrt((nm)/(rK))`

Answer

A

Explanation

`K.I = k' xx(1)/(n) = "constant"`
New spring constant for part is `k' = nK` Now `r` part are taken in parallelso `K_(eq) = nrk`
Time period `= 2pi sqrt((m)/(K_(eq))) = 2pi sqrt((m)/(m//k))`.