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The van't Hoff factor for 0.1 M Ba(NO(3)...

The van't Hoff factor for `0.1 M Ba(NO_(3))_(2)` solution is `2.74`. The degree of dissociation is

A

`91.3%`

B

`87%`

C

`100%`

D

`74%`

Text Solution

Verified by Experts

The correct Answer is:
B
Van't Hoff factor, `i=1+(n-1)alpha`
Here `n=3`
So `2.74+1+(3-1)alpha`
So, `alpha=0.87i.e. 87%`
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